금융공학프로그래밍3, Quiz2

1. Dictionary

icecream=dict(cheery=[12,100],cookies=[18,200],greentea=[15,140],mango=[10,200])

(1)

Change the price of ‘cookies’ as 13

icecream['cookies'][0]=13
icecream['cookies']

[13, 200]

(2)

Add the following information to the dictionary ‘icecream’. - ‘Strawberry’ is priced at 12 and inventory is 170. - ‘pistachio’ is priced at 15 and inventory is 100.

update_dict=dict(Strawberry=[12,170],pistachio=[15,100])
icecream.update(update_dict)
icecream

{'cheery': [12, 100],
 'cookies': [13, 200],
 'greentea': [15, 140],
 'mango': [10, 200],
 'Strawberry': [12, 170],
 'pistachio': [15, 100]}

2. Dictionary2

d1=dict(key1=1,key2=3,key3=2,key10=7)
d2=dict(key3=1,key2=2,key7=2,key5=4,key1=7,key9=8,key0=7)

(1)

Select the largest two values of the dictionary ‘d2’.

d2_list=list(d2.values())
d2_list.sort()
d2_list.reverse()
d2_list[0:2]

[8, 7]

(2)

Create a set of values which are the unique values of ‘d2’.

set(d2.values())

{1, 2, 4, 7, 8}

(3)

Write code that returns True if keys of ‘d1’ are all contained in the key of ‘d2’ and False otherwise.

set(d1.keys()) <= set(d2.keys())

False

(4)

Create a set of values which are common in both ‘d1’ and ‘d2’

set(d1.values())&set(d2.values())

{1, 2, 7}

3. if statement

For any arbitrary string object A, if the first character of A is ‘#’, we want it to be replaced with ‘*’. Otherwise, we want to add ‘*’ as the first character of A. Write appropriate code using an if statement for this

A="#abcde"

if A[0]=="#":
    A="*"+A[1:]
else:
    A="*"+A

A

'*abcde'

4. for loop

Calculate the following by using ‘for’ loop : \(\sum_{i=1}^{10} i^4\)

result=int()

for i in range(1,11):
    result+=i**4

result